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Aleksandr-060686 [28]
3 years ago
10

What angles are formed by perpendicular lines

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:

Right angle

Step-by-step explanation:

I thinks it's right angle

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Caden is a bird enthusiast and is trying to estimate the number of hawks living in his region. He traps 23 hawks and tags them.
serious [3.7K]
I believe the answer is 415
PLEASE MARK BRAINIEST!
6 0
2 years ago
Find the circumference and the area of a circle with radius 5 ft Use the value 3.14 for pi and do not round your answers. Be sur
Black_prince [1.1K]

Answer:

circumference: 31.41593 ft

Area: 78.53982 ft

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Interior angles of quadrilaterals<br><br>the sum of the four angles of any quadrilateral is 360​
MaRussiya [10]
Answers:
angle x= E. 118°
angle m= 131°

explanation:
the sum of the four angles of any quadrilateral
is 360
8 0
2 years ago
Slope Intercept Form:<br> put the equation in slope intercept form.<br> 14x = 6y - 12
Pavlova-9 [17]

Answer:

y = 7/2x + 2

Step-by-step explanation:

To put the equation in slope intercept form [ y = mx + b ], we need to solve for y.

14x = 6y - 12

~Subtract 6y to both sides

14x - 6y = -12

~Subtract 14x to both sides

-6y = -12 - 14x

~Divide -6 to everything

y = 2 + 7/3x

~Reorder

y = 7/2x + 2

Best of Luck!

8 0
2 years ago
Can some one solve these?!
ivolga24 [154]
All you need to solve these is a knowledge of the 3 main trigonometrical ratios.
I a right angled triangle where A is a non right angle:-

sin A = opposite / hypotenuse                         (hypotenuse is the sloping side)

cos A = adjacent / hyptenuse       ( the adjacent side is the one the angle 'sits' on)

tan A = opposite / adjacent   (  the opposite side is the one opposite the angle)

So to find the length of segment x in the first problem use

sin 61 = x / 50
 then
x  = 50*sin61  =  43.73 

and to find the length of y:-

cos 61 = y / 50
y = 60 cos 61 =  24.24

The other questions can be solved in a similar way.

7 0
3 years ago
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