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2 years ago

Can someone simplify8x + 5x please

Mathematics

2 answers:

igor_vitrenko [27]2 years ago

6 0

Answer:

13x

because you would comibne like terms, so you add the 8 and 5.

vodomira [7]2 years ago

6 0

Answer:

x=0

Step-by-step explanation:

Simplifying

8x + 5x = 0

Combine like terms: 8x + 5x = 13x

13x = 0

Solving

13x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '13'.

x = 0

Simplifying

x = 0

You might be interested in

How many zeros does the function f(x) = 2x14 − 14x6 + 27x3 − 13x + 12 have?

s2008m [1.1K]

<span>The function f(x) = 2x^14 − 14x^6 + 27x^3 − 13x + 12 has 2 zeros. </span>

4 0

2 years ago

Use the alternative form of the derivative to find the derivative at x = c (if it exists). (If the derivative does not exist at

KIM [24]

Answer:

The derivative of the function does not exist.

Step-by-step explanation:

The alternative form of a derivative is given by:

$f'(c)= \lim_{x \to c} \dfrac{f(x)-f(c)}{x-c}$

Our function is defined as:

h(x)=|x+8|

i.e. h(x)= -(x+8) when x+8<0

and x+8 when x+8≥0

i.e. h(x)= -x-8 when x<-8

and x+8 when x≥-8

Hence now we find the derivative of the function at c=-8

i.e. we need to find the Left hand derivative (L.H.D.) and Right hand derivative (R.H.D) of the function.

The L.H.D at a point 'a' is calculated as:

$\lim_{x \to a^-} \dfrac{f(x)-f(a)}{x-a}\\\\=\lim_{h \to0} \dfrac{f(a-h)-f(a)}{a-h-a}= \lim_{h\to 0} \dfrac{f(a-h)-f(a)}{-h}$

Similarly R.H.D is given by:

$\lim_{x \to a^+} \dfrac{f(x)-f(a)}{x+a}\\\\=\lim_{h \to 0} \dfrac{f(a+h)-f(a)}{a+h-a}= \lim_{h\to 0} \dfrac{f(a+h)-f(a)}{h}$

Now for L.H.D we have to use the function h(x) =-x-8

and for R.H.D. we have to use the function h(x)=x+8

L.H.D.

we have a=-8

$\lim_{x \to (-8)^-} \dfrac{h(x)-h(-8)}{x-(-8)}\\\\= \lim_{h \to0} \dfrac{h(-8-h)-h(-8)}{-8-h-(-8)}= \lim_{h\to 0} \dfrac{h(-8-h)-h(-8)}{-h}$

= $\lim_{h \to 0} \dfrac{8+h-8-0}{-h}= \lim_{h \to 0}\dfrac{h}{-h}=-1$

similarly for R.H.D.

$\lim_{x \to (-8)^+} \dfrac{h(x)-h(-8)}{x-(-8)}\\\\=\lim_{h \to 0} \dfrac{h(-8+h)-h(-8)}{-8+h-(-8)}= \lim_{h\to 0} \dfrac{h(-8+h)-h(-8)}{h}$

$\lim_{h \to 0} \dfrac{-8+h+8-0}{h}=\lim_{h \to 0}\dfrac{h}{h}=1$

Now as L.H.D≠R.H.D.

Hence, the function is not differentiable.

4 0

2 years ago

I think of a number, then divide by 4, then

Strike441 [17]

Answer:

332

Step-by-step explanation:

332 divided by 4 + 75 is 158

5 0

3 years ago

Read 2 more answers

Tia cut a 4 meter 8 centimeter wire into 10 equal pieces. Martha cut 540 centimeter wire into 9 equal pieces. how much longer is

Minchanka [31]

Answer:

Mia piece is 19.2cm longer than Tia's piece.

5 0

3 years ago

Read 2 more answers

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

Lynna [10]

Answer:

would multiply everything by the common denominator of 4

-3/4m - 1/2 = 2 + 1/4m....multiply everything by 4 and u get :

-3m - 2 = 8 + m

that will get rid of the fractions....but u could multiply by -4 ...giving u :

3m + 2 = -8 - m

Step-by-step explanation:

7 0

2 years ago