We have been given two points. 
and 
. We are asked to find the point B such that it divides line segment AC so that the ratio of AB to BC is 4:1.
We will use segment formula to solve our given problem.
When a point P divides segment any segment internally in the ratio 
, then coordinates of point P are:
![[\right x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2Cy%3D%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5Cleft%5D)
and 
.
Upon substituting our given information in above formula, we will get:
![[\right x=\frac{4(3)+1(3)}{4+1},y=\frac{4(9)+1(4)}{4+1}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B4%283%29%2B1%283%29%7D%7B4%2B1%7D%2Cy%3D%5Cfrac%7B4%289%29%2B1%284%29%7D%7B4%2B1%7D%5Cleft%5D)
![[\right x=\frac{12+3}{5},y=\frac{36+4}{5}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B12%2B3%7D%7B5%7D%2Cy%3D%5Cfrac%7B36%2B4%7D%7B5%7D%5Cleft%5D)
![[\right x=\frac{15}{5},y=\frac{40}{5}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B15%7D%7B5%7D%2Cy%3D%5Cfrac%7B40%7D%7B5%7D%5Cleft%5D)
![[\right x=3,y=8\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D3%2Cy%3D8%5Cleft%5D)
Therefore, the coordinates of point B would be 
.
Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.
Yes, it's miles true.
Consider the machine as Ax = 0. in which A is 4x5 matrix.
From given dim Nul A=1. Since, the rank theorem states that
The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation
rank A+ dim NulA = n
dim NulA =n- rank A
Rank A = 5 - dim Nul A
Rank A = 4
Thus, the measurement of dim Col A = rank A = five
And since Col A is a subspace of R^4, Col A = R^4.
So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.
Probability hit=40%=4/10
probability no hit=1-p (hit)=1-4/10=6/10
probability= p(hit)+p(hit)+p(hit)+p(hit)+p(hit)+p (no hit)+p (no hit)+p (no hit)
probability=4/10×4/10×4/10×4/10×4/10×6/10×6/10×6/10
=0.0022
( I think but I'm not 100% sure)
19 minutes I think just divide 323 and 17
Answer:
for question 13
- 130
- 50
- 50
- 130
- 130
- 50
- 50
- 130
Step-by-step explanation:
for 14
x. 150
y. 15
z. 150
i cant say that this is totally correct but im taking a educated guess
