Answer:28 bags with 17 cents left over
Step-by-step explanation: First, subtract the amount of 37.85 from what he started out with, 52.02. You should get 14.17.
Then, if we have 14 whole dollars and the bags each cost 50 cents, then we can just multiply 14 by 2, since each dollar equals 50 cents times 2.
EX: $1=50 cents x2. So 14 dollars x2 would be like saying the first amount 50 cents doubled. You should get 28 bags, with 17 cents left over :). Let me know if this makes sense! I really hope this helps you.
Answer:
128/3 - peas 128/9 corn
Step-by-step explanation:
it is too long
The Matchup are:
1. 1/3(24+15)=1/3•24+1/3•15 - distributive property
2. 101+(29+417) = (101+29) + 417 - associative property of addition.
3. (-14)+81 = 81 + (-14) - commutative property of addition.
4. -72 +0=-72 - additive identity.
5. 13/17•17/13=1 -multiplicative inverse.
<h3>What is a distributive property?</h3>
The distributive Property is one that connote the fact that if a factor is said to be multiplied by the sum or the addition of two terms, it is vital to multiply all of the two numbers by using the factor, and lastly carry out the addition operation.
Hence, The Matchup are:
1. 1/3(24+15)=1/3•24+1/3•15 - distributive property
2. 101+(29+417) = (101+29) + 417 - associative property of addition.
3. (-14)+81 = 81 + (-14) - commutative property of addition.
4. -72 +0=-72 - additive identity.
5. 13/17•17/13=1 -multiplicative inverse.
Learn more about distributive property from
brainly.com/question/2807928
#SPJ1
Answer:
C
Step-by-step explanation:
Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30