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Kay [80]
3 years ago
6

Factorise: a squared +8a -20

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0
Factor out the 4 in both equations
8a^2-20^2=(2^2 times a^2 times 2)-(2^2 times 5)
therefor it is also equal to
(2a)^2 times 2-(2^2 times 5)
we can force it into a difference of 2 perfect squares which is a^2-b^2=(a-b)(a+b)
(2a√2)^2-(2√5)^2=((2a√2)-(2√5))((2a√2)+(2√5))


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Mark drew two triangles and 8 arrows as part of a set of 13 shapes. The only other type of shape in the set is a circle. What fr
luda_lava [24]

Answer:

3/13

Step-by-step explanation:

First...

What we know

1. There is a set of 13 shapes.

2. With 2 triangles, 8 arrows, and circles.

Next...

Take the number of triangles and arrows and add them up.

2 + 8 = 10

Finally...

Convert it into the fraction 10/13 and subtract it by the total 13/13.

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3 0
3 years ago
A man invests $2000 in an account that pays 6.5% interest per year, compounded quarterly.
skelet666 [1.2K]

Answer:

The correct answer is a. $2275.28; b. 17.04 years

Step-by-step explanation:

Principal to be invested is $2000

Interest rate (r) per year is 6.5 quarterly.

Interest is calculated compoundly.

a. Time (t) for the investment is given to be 2 years.

Amount after two years is = Principal × ( 1+ \frac{r}{100n}) ^ {nt} where the value of n is 4.

⇒ A = 2000  × ( 1+ \frac{6.5}{400}) ^ {8}

⇒ A = $2275.28.

b. Now the value of A is given to be triple the principal = $ (3 × 2000).

Therefore we need to find the value of t.

⇒ 3 × 2000 =  2000  × ( 1+ \frac{6.5}{400}) ^ {4t}

⇒ ㏑ 3 = 4t × ㏑ ( 1.01625)

⇒ t = 17.04

Therefore it would take 17.04 years for the principal to triple.

5 0
3 years ago
Compute each sum below. If applicable, write your answer as a fraction.
Alex777 [14]

Answer:

First equation is -425

Second equation is 11.25

Step-by-step explanation:

First equation we can write as

\sum_{i=0}^7 5 \times (-2)^i

computing

When i=0 -> 5 \times (-2)^0 =5

When i=1 -> 5 \times (-2)^1 = -10

...

When i=7 -> 5 \times (-2)^7 = --640

then replacing each term we have

5  + (-10) + ( 20) + ( -40) +  (80) +( -160) +   320 + (-640) = -425

For the second equation we'll have 9 terms, solving in a similar fashion

When i=1 -> \frac{1}{4}1=0.25

When i=2 -> \frac{1}{4}2=0.50

When i=3 -> \frac{1}{4}3=0.75

...

When i=9 -> \frac{1}{4}9=2.25

So we have 0.25 + 0.50 + 0.75 + 1.00 + 1.25 + 1.50+ 1.75 +2.00 +2.25

4 0
3 years ago
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