Don’t know but uhh keep trying
The area, in square inches, outside the smaller region, but inside the larger region is 99π
<h3>How to determine the area, in square inches, outside the smaller region, but inside the larger region?</h3>
The given parameters are:
Radius, r1 = 1 inch
Radius, r2 = 10 inches
The area, in square inches, outside the smaller region, but inside the larger region is calculated as
Area = π(R^2 - r^2)
This gives
Area = π(10^2 - 1^2)
Evaluate the difference
Area = 99π
Hence, the area, in square inches, outside the smaller region, but inside the larger region is 99π
Read more about area at:
brainly.com/question/17335144
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Answer: 11.5
Step-by-step explanation:
It’s delta y over delta x so you would take any two combination of coordinates and subtract and divide. I used 57.50-23 over 5-2... this gets you 34.5 over 3. This is also equal to 11.5 :)
Answer:
x = 0
Step-by-step explanation:
→ Expand out the brackets
6 - 18x + 4x - 6 = 0
→ Collect all the like terms
-12x = 0
→ Now solve
x = 0
Answer:
The answer to this is 4 and 9 over 16.
Step-by-step explanation:
The expression is 3 + (2 + 8)^2 ÷ 4 × 1 over 2 to the power of 4 . it can be represented mathematically as
3 + (2 + 8)^2 ÷ 4 × (1/2)^4
using PEMDAS
parenthesis come first
3 + 10^2 ÷ 4 × (1/2)^4
exponential comes next
3 + 100 ÷ 4 × 1/16
3 + 25 × 1/16
3 + 25/16
(48 + 25)/16
73/16
4 9/16