Answer:
Babes, see the pic for the answer...
Answer:
The function is increasing from x = -2 to x = -1.
Step-by-step explanation:
The graph starts at -2 and is increasing by 1. it would not be "The function is increasing from x = 0 to x = 1" because it does not start at 0. it starts at -2. even though they both increase by 1, the starting point answer is always the best option.
Answer:
horizontal.
Step-by-step explanation:
it goes straight up
Answer: The correct option is (c) 
Step-by-step explanation: We are given to solve the following quadratic equation by the method of completing the square:

Also, we are to find the constant added on both sides to form the perfect square trinomial.
We have from equation (i) that

So,

Thus, the required solution is
and the value of the constant added is 
Option (c) is correct.
Answer:
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Step-by-step explanation: