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3 years ago

✓ 12.6

SAT

1 answer:

Nataly_w [17]3 years ago

6 0

Answer:

0.76027

Explanation:

Poisson distribution :

P(x) = (λ^x * e^-λ) ÷ x!

Average sales per day = 2.75 = λ

Using the poisson probability calculator ; the probability that the number of cars sold on a randomly selected day is greater than 1 is 0.76027.

This shows that the number of Times s the car dealer is likely to sell more than one car a day within a specified period of time is 0.76027 * 100 = 76.02 ( about 76%)

P(x > 1) = 0.76027

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The weight w of an object above the Earth varies inversely as the square of the distance d from the centre of the earth. If an a

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2 years ago

a helicopter flies parallel to the ground at an altitude of 1/2 kilometer and at a speed of 2 kilometers per minute. if the heli

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The Pythagoras' theorem and the uniform motion allows to find the answer for the rate of change of distance is

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The distance is the length of the segment that a white house wing with the helicopter, this can be found using the Pythagoras' theorem

R = $\sqrt{x^2 + y^2}$

Where R is the distance, x is the horizontal distance where the helicopter flies and y is the vertical distance that corresponds to the flight height

y = 500 m

Since the helicopter flies at constant speed, we can use the uniform motion relation

$v_h$ = $\frac{x}{t}$

x = $v_h$ t

Where $v_h$ is the speed of the helicopter and t is the time

We substitute

r = $\sqrt {(V_h \ t)^2 + y^2}$

Kinematics defines velocity as the change of position in the unit of time

$v = \frac{dR}{dt}$

$v = \frac{1}{2} \ \frac{2 ( v_h t) v_h}{ \sqrt{(v_h t)^2 + y^2} }$

$v = \frac{v_h^2 \ t}{ \sqrt{(v_h t)^2 + y^2} }$

This expression is the change in distance as a function of time for a given speed. In the exercise, this speed is requested for a time of one minute, for the helicopter speed of

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Let's calculate

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In conclusion using the Pythagoras' theorem and the uniform motion we can find the answer for the rate of change in distance is

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Learn more here: brainly.com/question/343682

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