Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
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The answer is 8i.
i = √(-1)
√(-64) = √((-1) * 64)
= √(-1) * √64
= i * √8²
= i * 8
= 8i
Answer:
x=
3
2
=0.667
x=3
Step-by-step explanation:
Answer:
4/27
Step-by-step explanation:
F(x) = 4(1/3)^x
Let x =3
F(3) = 4(1/3)^3
Exponents first
F(3) = 4 * 1/27
Then multiply
f(3) = 4/27
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