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Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

8 0

I don't now just need points

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Please help, it's on Pythagoras theorem!

kondor19780726 [428]

C squared = a squared+ b squared (formula)

so therefore
(c longest side) (this is your x)
(a and b shorter sides).

C squared = 5 squared + 3 squared
C squared = 25 + 9
C squared = 31

Then you find the square root of c (which is just getting rid of the squared sign) and the square root of 31 And that is your answer

Hope this helps!!

3 0

3 years ago

Muna has a piece of string that is 4 2/3 yards long. If she cuts it into pieces that are each 2/3 yard long, how many pieces of

bonufazy [111]

To start you would turn 4 2/3 into a mixed number by multiplying 4 and 3 and adding 2. Your mixed number would be 14/3. Then, you want to find how many 2/3 yard long pieces of string will fit into 14/3 so you devid 14/3 by 2/3 and you get 7. So 7 2/3 yard pieces of string will fit into 4 2/3.

To check your work you can multiply 2/3 by 7 and you will get 4 2/3.

3 0

3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.