Based on the given information, which conjecture is invalid?

Mathematics

1 answer:

KIM [24]3 years ago

5 0

The answer is C.
C is the only answer that doesn’t name an animal that has 4 legs.

You might be interested in

M<6=(x+10), m<2=(x+15)<br> <6 and <2 are alternate interior angles

djverab [1.8K]

Answer:

ano ang pinag kaiba noon kaysa ngayon

5 0

3 years ago

Segment AB is congruent to segment AB.

galben [10]

Step-by-step explanation:

i don't know sister/ boy

7 0

3 years ago

What is the area of this polygon in square units ?

Maru [420]

Answer:

9 units²

Step-by-step explanation:

This is a trapezium.

The length of the two parallel lines (on top and bottom) are 5 units and 1 units.

The height of the trapezium is 3 units. Using these information, we can apply the formula for area of trapezium to find the answer.

Area = 1/2 (5 + 1) x 3 = 9 units²

7 0

3 years ago

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

3 years ago

What expression is equivalent to 1/5•1/5•1/5•1/5

lara31 [8.8K]

The expression will be 589/15

8 0

3 years ago