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3 years ago

Which order from least to greatest of 2.8, 2.8x10², 2.8x10⁻3, 2.8x10⁴, 2.8x10⁻5

Mathematics

2 answers:

Dominik [7]3 years ago

7 0

2.8x10^-5 ; 2.8x10^-3 ; 2.8 ; 2.8x10^2 ; 2.8x10^4

Anna007 [38]3 years ago

3 0

Answer:

2.8x10⁻5, 2.8x10⁻3, 2.8, 2.8x10², 2.8x10⁴

Step-by-step explanation:

The greater the exponent, the greater the number. In the negative case however, as the negative numbers become greater, they become less and less.

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3/8 rounded to the nearest thousand

tresset_1 [31]

Answer:

0.38

Step-by-step explanation:

First, we convert the fraction to a decimal number by dividing the numerator by the denominator:

3 / 8 = 0.375

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Integer Part: 0

Fractional Part: 375

Now, we will make the Fractional Part just two digits (nearest hundredth) by using our rounding rules.*

In this case, Rule II applies, so 3/8 (or 0.375) rounded to the nearest hundredth in decimal format is:

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Answer:

D. x = 2

Step-by-step explanation:

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2 years ago

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24 rainy days out of 36 days

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2 years ago

An SRS of 25 recent birth records at the local hospital was selected. In the sample, the average birth weight was x = 119.6 ounc

Evgen [1.6K]

Answer:

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X}= \mu = 119.6$

And now for the deviation we have this:

$SE_{\bar X} = \frac{6.5}{\sqrt{25}}=1.3$

So then the correct answer for this caee would be:

c. 1.30 ounces.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X}= \mu = 119.6$

And now for the deviation we have this:

$SE_{\bar X} = \frac{6.5}{\sqrt{25}}=1.3$

So then the correct answer for this caee would be:

c. 1.30 ounces.

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