answer:
(a).
Equation of circle is <u>x²</u><u> </u><u>+</u><u> </u><u>y²</u><u> </u><u>-</u><u> </u><u>2</u><u>5</u><u> </u><u>=</u><u> </u><u>0</u>
(b).
(-5, 0) » yes
(√7, 1) » no
(-3, √21) » no
(0, 7) » no
Step-by-step explanation:
(a).
If centred at origin, centre is (0, 0)
General equation of circle:
but g and f are 0:
Answer:
t = 2.52 seconds
Step-by-step explanation:
h=139-15t-16t^2
We want to know when the ball hits the ground
That would be when h=0
0 = 139-15t-16t^2
We can use the quadratic formula to find t
t = -b ± sqrt(b^2-4ac)
----------------------
2a
where a = -16 b = -15 and c = 139
t = -(-15) ± sqrt((-15)^2-4(-16)139)
----------------------
2(-16)
t = (15) ± sqrt(225+8896)
----------------------
-32
t = (15) ± sqrt(9121)
----------------------
-32
t = 15+ sqrt(9121) t = 15- sqrt(9121)
-------------------- or -------------------
-32 -32
-3.453247707 or 2.515747707
Since time cannot be negative
2.515747707
Round to the nearest hundredth
t = 2.52 seconds
A. To be able to have the 2 sides ( the 2 triangles) line up correctly, Net A would be the correct one.
B. AB = 3
BC = 5
CD = 9.4
C. Surface area:
9.4 x 5 = 47
9.4 x 3 = 28.2
9.4 x 4 = 37.6
3 x 4 = 12
Total: 47 + 28.2 + 37.6 + 12 = 124.8 sq. in.
Answer:
10
Step-by-step explanation:
use pythagorean theorm
√(8^2+6^2) = 10
