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lukranit [14]
3 years ago
11

What equation is graphed in this figure? y−4=−13(x+2) y−3=13(x+1) y+2=−3(x−1) y−5=3(x−1) Number graph ranging from negative four

to four on the x and y axes. A line is drawn on the graph that passes through begin ordered pair negative one comma four end ordered pair and begin ordered pair one comma negative two end ordered pair
will give brainliest

Mathematics
2 answers:
zlopas [31]3 years ago
6 0

Answer:

Correct answer is 8x-9=23

I took the test

omeli [17]3 years ago
5 0

Answer: The correct option is 3.

Explanation:

It is given that the line passes through (-1,4) and (1,-2).

The slope of the line is,

m=\frac{y_2-y_1}{x_2-x_1}

The slope of the given line is,

m=\frac{-2-4}{1-(-1)} =\frac{-6}{2}=-3

The point slope form of a line is,

y-y_1=m(x-x_1)

Where, m is the slope.

Since slope is -3 and point is (-1,4), then the equation of line is,

y-4=-3(x+1)

Since slope is -3 and point is (1,-2), then the equation of line is,

y+2=-3(x-1)

Therefore, the correct option is 3.

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Answer:

A) $ \frac{1}{5} $

B) - 5

C) Not Possible

D) 5

E) $ \frac{-1}{5} $

  • Step-by-step explanation:
  • All integers are rational numbers. But not all rational numbers are integers.
  • All whole numbers are integers. But not all integers are whole numbers.

I am a rational number but not an integer. Located on the right of 0.

This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form $ \frac{p}{q} $.

From, the options $ \frac{1}{5} $ would fit this description.

I am a rational number and an integer but not a whole number.

This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.

I am a whole number but not an integer.

This is clearly not possible because all whole numbers are a subset of integers.

I am a rational number, a whole number and an integer.

This means it is a positive integer. 5 would fit this description.

I am a rational number but not an integer; located on the left side of 0.

This means it is a negative number. $ -\frac{1}{5} $ should be the answer.

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Find the possibility of rolling even numbers three times, using a six-side die number from 1 to 6
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\frac{1}{8}

Step-by-step explanation:

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Number of sides with even numbers = 3

P( rolling an even number 1 time) = \frac{3}{6} = \frac{1}{2}

P(rolling even number 3 times) = \frac{1}{2} x \frac{1}{2}  x \frac{1}{2} = \frac{1}{8}

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1\frac{1}{2}

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Step-by-step explanation:

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