3 years ago

Find three consecutive odd integers such that the sum of the smallest and twice the second is 14 more than the third.

Mathematics

1 answer:

blondinia [14]3 years ago

3 0

Ans 7, 9, 11

Step-by-step explanation:

Think of it as an equation. You have 3 integers x, y, and z.

x + 2y = z + 14.

Plug in consecutive odd integers, picking your next set of trial and error integers based on how far off the equation is.

In this case, 7 + (2 * 9) = 11 + 14

In this example, it took me three attempts to get the correct answer.

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