Question

Find three consecutive odd integers such that the sum of the smallest and twice the second is 14 more than the third.

Answer 1

Ans 7, 9, 11

Step-by-step explanation:

Think of it as an equation.  You have 3 integers x, y, and z.

x + 2y = z + 14.  

Plug in consecutive odd integers, picking your next set of trial and error integers based on how far off the equation is.

In this case, 7 + (2 * 9) = 11 + 14

In this example, it took me three attempts to get the correct answer.