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3 years ago

PLEASE HELP!! Urgent! :((

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

6 0

Answer:

the angle is 245°

Step-by-step explanation:

that is a pentagon, (a shape with 5 sides)

we know 4 of the angles in the pentagon

the sum of those 4 angles is

58°+100°+112°+25°=295°

to find a shapes total amount of °, the equation is (n-2)x180°

(5-2)x180°

=540°

540°-295°=245°

x=245°

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Dividing integers.word problems.

Alex787 [66]

Answer:

Step-by-step explanation:

Sign. We will get a positive number. So a positive divided by positive is positive and a negative divided by a negative is also positive. Now if the two numbers have different signs.

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3 years ago

HELP PLEASE 25 POINTS

erastova [34]

Answer:

$15, $8, $1, respectively

Step-by-step explanation:

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3 years ago

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Julio and his friend ordered five pizzas they know that 1/3 of a pizza will serve one person how many servings are there? Please

Ket [755]

Okay, so if 1/3 of a pizza is a serving, you would have to know that 1 pizza contains 3 servings.

Multiply 5*3 for your answer.

5*3= 15

That is 15 servings.

I hope this helped you!

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4 years ago

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.

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4 years ago

In a circle with a radius of 27 2/5 in., an arc is intercepted by a central angle of 7π/4 radians.

VikaD [51]

Arc Length = radius * Angle in radians
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Source:
http://www.1728.org/radians.htm

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3 years ago

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