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2 years ago

Please help me solve b,c,d asap i need it in 10 min!!!

Mathematics

2 answers:

aksik [14]2 years ago

8 0

X/3 - 5 is the answer

Vaselesa [24]2 years ago

7 0

Answer:

These answer are written in standard form

Step-by-step explanation:

D. The sum of four and twice a number = 2x+4

C. Seven more than three times a number, all multiplied by itself = 3x+7

B. Nine less than a number, all divided by three = $\frac{n-9}{3}$

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Mark bought three pairs of shorts and one pair of shoes. If the shoes cost $25 and he spent

Aleonysh [2.5K]

Answer:

17.95 :)

Step-by-step explanation:

25-78.85= 53.85, and 53.85/3= 17.95 so each pair of shorts costed 17.95

8 0

3 years ago

Convert 2000 g/l to the unit g/ml

balu736 [363]

$\frac{2 \000 g}{l} = \ ? \ \frac{g}{ml} \\ \\ 1 \ l = 1 \ 000 \ ml \\ \\\frac{2\ 000 \ g}{l} =\frac{2 \000 \ g}{1 \000\ ml} = 2.0 \ \ \frac{g}{ml}$

6 0

3 years ago

Read 2 more answers

Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

Jobisdone [24]

Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

5 0

3 years ago

Select Repeating or Nonrepeating to correctly classify each decimal. Repeating Nonrepeating 7.777777... 6.213 KON 5.1152535 4.04

mash [69]

Answer:

repeating non repeating non repeating non repeating

Step-by-step explanation:

7 0

3 years ago

Part 2 out of 2

olganol [36]

Answer:

more than your rent

Step-by-step explanation:

hahahaha

4 0

2 years ago