If 
is the unknown concentration of the second solution, then each mL of this solution that is used in the new one contributes 
mL of acid.
There are 40 mL of the new solution, and one quarter is made up of 20% acid while the remaining three-quarters is made up of the solution - that is, 10 mL of a 20% acid solution are used, so that its contribution is 0.2(10 mL) = 2 mL of acid, while 30 mL of the solution are used, so it contributes 
of acid.
In this new solution, we want to get a concentration of 32% acid, so it should contain 0.32(40 mL) = 12.8 mL of acid. Then the total amount of acid in the new solution satisfies
so the second solution has a concentration of 36%. The equation used here is the same as the first choice (a),
Answer: 33.33...% percent error
Step-by-step explanation: To find the percent error from 16 to 12, we will be using the "percent error" equation.
difference = percent error x actual
To find the difference, subtract 12 from 16, which is 4.
4 = percent error x actual
The actual is 12 because, because a percent error from 16 to 12, means that the actual was 12 and the estimate was 16 because 16 was to "12"
4 = percent error x 12 (Solve for p, percent error)
4/12 = p
0.33... = p
Multiply 0.33.. by 100, to get the percent error.
0.33... x 100 = 33.33... or 33.33...%
Answer:
t t f t t f
Step-by-step explanation:
One is positive and the other is negative
Answer:
Step-by-step explanation:
<h3>Polynomial:</h3>
p(x) = ax³ + bx + x
Let g(x) = x² + kx + 1 .
g(x) is a factor of p(x). So, p(x) is divided by g(x), the remainder will be 0.
Divide p(x) by g(x) using long division method. {attached as an image}.
By doing long division, we get the remainder.
Remainder = bx - ax + k²ax + ka + c
= (b - a + k²a)x+ [ka + c]
Remainder = 0
b - a + k²a = 0 and ka + c = 0
ka + c = 0
ka = -c
k = -c/a ----------------(I)
b - a + k²a = 0
![\sf b -a + \dfrac{c^2}{a^2}*a=0 -------[From \ (I)]\\\\b - a + \dfrac{c^2}{a}=0\\\\Multiply \ the \ above \ equation\ by \ a \\\\ab - a^2 + c^2 = 0\\\\\\](https://tex.z-dn.net/?f=%5Csf%20b%20-a%20%2B%20%5Cdfrac%7Bc%5E2%7D%7Ba%5E2%7D%2Aa%3D0%20%20%20-------%5BFrom%20%5C%20%28I%29%5D%5C%5C%5C%5Cb%20-%20a%20%20%2B%20%5Cdfrac%7Bc%5E2%7D%7Ba%7D%3D0%5C%5C%5C%5CMultiply%20%5C%20the%20%5C%20above%20%5C%20equation%5C%20by%20%5C%20a%20%5C%5C%5C%5Cab%20-%20a%5E2%20%2B%20c%5E2%20%3D%200%5C%5C%5C%5C%5C%5C)
ab = a² - c²
Hence, proved.
