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ArbitrLikvidat [17]
3 years ago
10

Solve the right triangle below. Round all your answers to the nearest tenth. Measure of angle X = ______

Mathematics
1 answer:
umka21 [38]3 years ago
3 0
The answer would be 8.5


Remember the Pythagorean theorem. A^2+ B^2= C^2. The hypotenuse, or 9 (in this question) will always be C
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(3x^4y^5) ^ 3/7 in radical form
kobusy [5.1K]

The expression in radical form is (\sqrt[7]{3x^4y^5}) ^3

In order to express the given indices expression in radical form, we need to ensure there is a square root present in the resulting expression.

According to the law of indices,

a^{m/n} = \sqrt[n]{m}

Given the indices (3x^4y^5) ^ {3/7}

Comparing with the general formula, we will see that:

m = 3

n = 7

a = 3x^4y^5

Applying the law of indices:

(3x^4y^5) ^ {3/7} = (\sqrt[7]{3x^4y^5}) ^3

Hence the expression in radical form is (\sqrt[7]{3x^4y^5}) ^3

Learn more here: brainly.com/question/6755932

3 0
2 years ago
Help me please I have no idea on how to do this. Thanks
andriy [413]
1) P=2w +2l
46=2w +14
32=2w
16= w or width

2) A=lw
A=7 x 12
A= 84

3) A= 12 x 21
A= 252
6 0
3 years ago
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
A street that is 360 feet long is covered in snow city workers are using a snow plow to clear the street a tire on the snow plow
belka [17]

Answer:

Radius of tire=0.58 meter

Step-by-step explanation:

as we know that the

Circumference of the tire=2*3.14*r

and it needs to rotate 30 times to cover the street distance of 360 feet

So, the below equation would be used to find the radius of tire in the meters

360/3.28084=30*2*3.14*r

r=0.5824203822 meters

Hence

Radius=0.58 meter

3 0
2 years ago
Please solve this <br> The real one don't solve till you see the equation
Afina-wow [57]
The answer is 40 good luck
7 0
3 years ago
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