<span>a) We know that the correct answer will be the square root of 256 since the competition area is a square with an area of 256 meters. And since 10^2 = 100 which is less than 256, the answer has to be greater than 10. And since 20^2 = 400 which is greater than 256, the answer also has to be less than 20. Therefore the answer has to be between 10 and 20.
b) The last digit has to be either a 4 or a 6. The units digit is the only digit that will contribute to the units digit of the square. And 0^2 = 0, 1^2 = 1, 2^2 = 4, 3^2 = 9, 4^2 = 16, 5^2 = 25, 6^2 = 36, 7^2 = 49, 8^2 = 64, 9^2 = 81. Of the 10 possible digits, only the values 4 and 6 have a square that has an units digit of 6.
c) The square root of 256 based up (a) and (b) above has to be either 14, or 16. So the dimensions are either 14x14 meters or 16x16 meters.</span>
Get n to one side
-1/5=-2/5n
divide both sides by -2/5
n=1/2
Answer:
Option A - Neither. Lines intersect but are not perpendicular. One Solution.
Option B - Lines are equivalent. Infinitely many solutions
Option C - Lines are perpendicular. Only one solution
Option D - Lines are parallel. No solution
Step-by-step explanation:
The slope equation is known as;
y = mx + c
Where m is slope and c is intercept.
Now, two lines are parallel if their slopes are equal.
Looking at the options;
Option D with y = 12x + 6 and y = 12x - 7 have the same slope of 12.
Thus,the lines are parrallel, no solution.
Two lines are perpendicular if the product of their slopes is -1. Option C is the one that falls into this category because -2/5 × 5/2 = - 1. Thus, lines here are perpendicular and have one solution.
Two lines are said to intersect but not perpendicular if they have different slopes but their products are not -1.
Option A falls into this category because - 9 ≠ 3/2 and their product is not -1.
Two lines are said to be equivalent with infinitely many solutions when their slopes and y-intercept are equal.
Option B falls into this category.
if the degree of the expression of the numerator is greater than that of the denominator, the rational expression has no horizontal asymptote.
I believe in standard form this would be 31/2 + 27i/2
