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Valentin [98]
3 years ago
10

1 + 4 = 52 + 5 = 123 + 6 = 218 + 11 = ?​

Mathematics
1 answer:
Finger [1]3 years ago
4 0
8 + 11 = 19
The answer is 19
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Can someone help with this question
Zielflug [23.3K]

Answer:

<1= 60

<2=120

<3=60

<4=60

<5=120

<6=120

<7=60

Step-by-step explanation:

6 0
3 years ago
The radius of a circle is 1 kilometer. What is the area?Give the exact answer in simplest form.____ square kilometers
choli [55]

Ok, so;

Let me draw the figure here below:

We know that the area of a circle can be found using the next equation:

Area = πr².

Where r is the radius and π is a number.

So, the area of this circle, will be:

Area = π(1km)²

Area = π km²

7 0
1 year ago
Berries are $3 per pound. Which inequality shows the number N of pounds you can buy if you have $20?
Lady bird [3.3K]

Answer:

N≤(20/3);    Kindly rate

Step-by-step explanation:

The number N of pounds you can buy if you have $20, given that the cost of Berries is $3 per pound will be less or equal to (20/3)

7 0
3 years ago
Read 2 more answers
e chairman of the statistics department in a certain college believes that 70% of the department’s graduate assistantships are g
8_murik_8 [283]

Answer:

38.46% probability that the sample proportion will NOT be between 0.60 and 0.73

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

For a proportion p in a sample of size n, we have that \mu = p, \sigma = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.7, n = 50

So

\mu = 0.7, \sigma = \sqrt{\frac{0.7*0.3}{50}} = 0.0648

What is the probability that the sample proportion will NOT be between 0.60 and 0.73?

This is 1 subtracted by the probability that it is between 0.6 and 0.73.

Probability it is between 0.6 and 0.73

pvalue of Z when X = 0.73 subtracted by the pvalue of Z when X = 0.6. So

X = 0.73

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 0.7}{0.0648}

Z = 0.46

Z = 0.46 has a pvalue of 0.6772

X = 0.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.6 - 0.7}{0.0648}

Z = -1.54

Z = -1.54 has a pvalue of 0.0618

0.6772 - 0.0618 = 0.6154

NOT be between 0.60 and 0.73?

1 - 0.6154 = 0.3846

38.46% probability that the sample proportion will NOT be between 0.60 and 0.73

5 0
4 years ago
X^2 + 1/2x + = 2 + <br> Help please
Gennadij [26K]

Answer:

Step 2:

For Completing the square,

(\frac{1}{2} coefficient\ x)^{2} =(\frac{1}{2}\times \frac{1}{2})^{2}=\frac{1}{16}

Add half coefficient of x square on both the side we get

x^{2}+\dfrac{x}{2}+\frac{1}{16}=2+\frac{1}{16}

Step-by-step explanation:

Solve:

2x^{2}+x-4=0

2x^{2}+x=4

Solution:

Step 1:

Dividing both the side by two we get

x^{2}+\dfrac{x}{2}=2

Step 2:

For Completing the square,

(\frac{1}{2} coefficient\ x)^{2} =(\frac{1}{2}\times \frac{1}{2})^{2}=\frac{1}{16}

Add half coefficient of x square on both the side we get

x^{2}+\dfrac{x}{2}+\frac{1}{16}=2+\frac{1}{16}

Step 3:

We know (a +b)^{2} = a^{2}+2ab +b^{2}

(x+\frac{1}{4})^{2}=\frac{33}{16} \\ \\(x+\dfrac{1}{4})=\pm \sqrt{\dfrac{33}{16}} \\\\x=-\dfrac{1}{4}\pm \sqrt{\dfrac{33}{16}}

6 0
4 years ago
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