Hello!
So if each box has 14 favors, what we need to do is add until we have enough, or more than enough for each of the children that will be at the party to get two of them.
So to start, 14+14=28. There are 28 children going, but each child must have two favors, not one. So, we simply add on two more boxes. 28+14=42, 42+14=56. So, we need 56 favors for each child to get two.
You could multiply to make this problem faster, but adding works out easier in my head. Sorry to drag it out!
So to make it simple, you need four boxes of favors for each child to get two.
Hope this helps, have an awesome day!
X<0
y > 0
so x is negative and y is positive
Quad. II
answer
Quadrant II
Answer: y=1/12x+43/12
Step-by-step explanation:
Use the slope formula and then change it to slope intercept form.
You can’t evaluate that I’m pretty sure
