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3 years ago

Hi everyone! I have a question!

Mathematics

2 answers:

ahrayia [7]3 years ago

7 0

Answer:

Step-by-step explanation:

area of unshaded circle:

A=π*r^2=π*1=π

we have 2 circles so the area of both circles are 2π

area of the large circle is A(l)=Π*3^2=Π*9=9Π

area of the shaded region: A(s)=9Π-2Π=7Π

Tju [1.3M]3 years ago

3 0

Answer:

7π

Step-by-step explanation:

SO first find the area of the whole circle

which has a radius of 3

a=πr^2

So 3^2=9

9π

Now the two circles which are the same in area due to having the same radius

so if you plug in the 1 for radius the answer would just be π or 1π

now multiply that by 2 becuase there are 2 identical circles

π*2=2π

Now subtract

9π-2π=7π

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motikmotik

Answer:

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Step-by-step explanation:

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3 years ago

Find the area of a plane figure bounded by lines

natulia [17]

Answer: 4.5

Step-by-step explanation:

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6 ⇒ x² + x - 2 = 0 ⇒ (x + 2)(x - 1) = 0 ⇒ x = -2, x = 1

Now, integrate from x = -2 to x = 1

$\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,$ the bottom of the integral is -2

= $\int\limits^1_2 {x+6-x^{2}-2x-4 } \,$

= $\int\limits^1_2 {-x^{2}-x+2 } \,$

= $\frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,$

= $(\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))$

= $(\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)$

= $\frac{-9}{3} + \frac{3}{2} +6$

= -3 + 1.5 + 6

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3 years ago