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baherus [9]
3 years ago
7

Eleven letters spelling "probability" are placed in a bag. You pick one, replace it, and then pick another. What is the probabil

ity of picking a P and then a I?
Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0

Answer:

It is 2/121.

Step-by-step explanation:

For the first draw, the probability of picking P is 1/11 since there is only one P letter in the 11 letters. If we replace the P after drawing, then for the second draw, the probability of drawing I is 2/11 since there are 2 I's in the 11 letters.

Since the events are seperate, the probability of picking P and then picking I is (1/11)x(2/11) = 2/121.

I hope this answer helps.

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juin [17]

Answer:

8

Step-by-step explanation:

use trig functions

2 sides and 1 angle given

Sides given

  • hypotenuse -> x
  • opposite side to 30˚ -> 4

Angle

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trig function associated with hyp and opp is sin

sin(x) = opp/hyp

substitute

sin 30˚ = 4/x

solve for x

0.5 = 4/x

0.5x = 4

x = 8

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Answer:

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Step-by-step explanation:

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We need a denominator out of 100

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Answer:

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bazaltina [42]

Answer:

b

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HJ
Olin [163]

Answer:

19 degrees

Step-by-step explanation:

From the question given

The interior angles are x+12 and x - 3

Exterior angle is <IJK = 5x-6

Using the rule that states that the sum of interior angle of a triangle is equal to the exterior

<JHI + <HIJ = <IJK

x+12 + x-3 = 5x - 6

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2x - 5x = -6-9

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Recall that <IJK = 5x - 6

<IJK = 5(5) - 6

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Hence the measure of <IJK is 19 degrees

8 0
2 years ago
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