<span>2x^3+3x^2-30x+7/x-3 divide</span>
Answer:
There are 60 monkeys in the Zoo
Step-by-step explanation:
In this question, we are asked to calculate the number of monkeys in a Zoo given some information to use.
Let’s have the total number of monkeys be m.
60% are going monkeys. This means number of young monkeys is 0.6m.
The number of baby and old monkeys is obviously 0.4m.
Ratio of baby to old monkeys is 3:1. This means if we splitter 0.4m into 4, number of baby monkeys is 0.3m while number of old monkeys is 0.1m
Now, subtracting the number of baby monkeys from young monkeys give a total of 18 monkeys.
Let’s project this mathematically;
This means ;
0.6m - 0.3m = 18
0.3m = 18
m = 18/0.3
m = 60
There are 60 monkeys in the zoo
Answer:
60
Step-by-step explanation:
We have to find least common denominator for these fractions or we just have to find the least common multiple for 15, 6 and 4
In order to find the least common multiple, we have to represent these numbers as factors of prime numbers:
15 = 3 * 5
6 = 2 * 3
4 = 2 * 2
Least common multiples will be common factors (considering that there are no more than of them in other numbers) and the uncommon factors. Then, we can write that:
2 * 2 * 3 * 5 = 60 (there are two 2's, one common 3 and an uncommon 5)
The denominator will be 60 for the least common multiples.
To be able to quickly solve this, we can temporarily make 5.47 into 547
Now, we can divide 547 by 12.
Now, we can round up from 45.5 to get 46.
However, we originally moved our decimal 2 places over, so now we must move it 2 places again.
46 ⇒ 0.46
The correct answer is $0.46
The answer is $906
hope i helped
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