Question

A spinner has five equal parts labeled from 1 to 5. The spinner is spun twice. What is the probability of getting a 4 twice in a row?

Answer 1

$|\Omega|=5^2=25\\ |A|=1\\\\ P(A)=\dfrac{1}{25}=4\%$

Answer 2

Answer:

$\frac{1}{25}$  

Step-by-step explanation:

Given : A spinner has five equal parts labeled from 1 to 5.

           The spinner is spun twice.

To Find: What is the probability of getting a 4 twice in a row?

Solution:

Numbers on spinner = {1,2,3,4,5}=5

Favorable outcome = {4}=1

So, probability of getting 4 on first spin =$\frac{1}{5}$

Now probability of getting 4 on second spin =$\frac{1}{5}$

So,  the probability of getting a 4 twice in a row = $\frac{1}{5} \times \frac{1}{25}$

                                                                               = $\frac{1}{25}$  

Hence the probability of getting a 4 twice in a row is  $\frac{1}{25}$