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Fantom [35]
3 years ago
15

A spinner has five equal parts labeled from 1 to 5. The spinner is spun twice. What is the probability of getting a 4 twice in a

row?
Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
8 0

|\Omega|=5^2=25\\ |A|=1\\\\ P(A)=\dfrac{1}{25}=4\%

ella [17]3 years ago
7 0

Answer:

\frac{1}{25}  

Step-by-step explanation:

Given : A spinner has five equal parts labeled from 1 to 5.

           The spinner is spun twice.

To Find: What is the probability of getting a 4 twice in a row?

Solution:

Numbers on spinner = {1,2,3,4,5}=5

Favorable outcome = {4}=1

So, probability of getting 4 on first spin =\frac{1}{5}

Now probability of getting 4 on second spin =\frac{1}{5}

So,  the probability of getting a 4 twice in a row = \frac{1}{5} \times \frac{1}{25}

                                                                               = \frac{1}{25}  

Hence the probability of getting a 4 twice in a row is  \frac{1}{25}  

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