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Nana76 [90]
3 years ago
11

The differences of 4 and a number x is 14

Mathematics
2 answers:
shutvik [7]3 years ago
6 0

Answer:

x=18

Step-by-step explanation:

x-4=14

  +4  +4

x=18

lidiya [134]3 years ago
5 0
I think it might be 10? :)
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Point P is the center of the circle below. What is the exact area
Ber [7]

Answer:

192π unit²

Step-by-step explanation:

Given that :

Radius = 24

Area of circle = πr²

Area = π*24²

Area = 576π in²

The Shaded area is 120°

Entire Circumference = 360°

Hence, shaded area = 120°/ 360° = 1/ 3 of the area

1/3 * 576π in²

= 192π unit²

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2 years ago
Patricia can drive 36 kilometers for every 3 liters of gas she puts in her car.
zloy xaker [14]
36 km
--------- = 12 km/liter
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Pat can drive 12 km per liter of gas.

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3 years ago
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What value should be added to the expression to create a perfect square?
Lilit [14]
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8 0
3 years ago
The temperature in the late afternoon
Fantom [35]

Answer:

-7.5 - (8.5 + 5)

Step-by-step explanation:

We just add together the values of how much it dropped at different parts of the day, and subtract them from what we started with. The parenthesis are important cause we want to know what the total temperature drop for the day was before we subtract it to get the actual temperature we end up with.

6 0
3 years ago
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the half life of c14 is 5730 years. Suppose that wood found at an archeological excavation site contains about 35% as much C14 a
Furkat [3]

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau} (Eq. 1)

Where:

\frac{dm}{dt} - First derivative of mass in time, measured in miligrams per year.

\tau - Time constant, measured in years.

m - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt

\ln m = -\frac{1}{\tau} + C

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (Eq. 2)

Where:

m_{o} - Initial mass of isotope, measured in miligrams.

t - Time, measured in years.

And time is cleared within the equation:

t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right]

Then, time constant can be found as a function of half-life:

\tau = \frac{t_{1/2}}{\ln 2} (Eq. 3)

If we know that t_{1/2} = 5730\,yr and \frac{m(t)}{m_{o}} = 0.35, then:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.35

t \approx 8678.505\,yr

The wood was cut approximately 8679 years ago.

5 0
3 years ago
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