Answer: 1
Step-by-step explanation:
Rewrite as (i^4)^6
Rewrite i^4 as 1
Rewrite i^4 as (i^2) ^2
((i^2)) ^2)6
Rewrite i^2 as -1
((-1) ^2) 6
Raise -1 to the power of 2
1^6
One to any power is 1.
Just do 5 1/5 divided by 1 2/5
Answer:
784
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given: Let A be the event that the first die lands on 2 and B be the event that the second die lands on 2.
To find:
P(A), the probability that the first die lands on 2
P(B), the probability that the second die lands on 2
P(A and B): the probability that the first die lands on 2 and the second die lands on 2
Solution:
Probability refers to chances of occurrence of some event.
Probability = number of favourable outcomes/total number of outcomes
Sample space = 
Total number of outcomes = 6
For P(A):
Number of favourable outcomes = 1
So,

For P(B):
Number of favourable outcomes = 1
So,

P(A and B) = 
Yes, A and B are independent events as happening of each of the event does not depend on the other.
I will go less as i write them:
.4 .04 .004 .0004