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andrey2020 [161]
3 years ago
9

A worm moves forward 3/8 inch every 5 minutes for 1 hour 25 minutes. How far does the worm move in this time? Explain

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

6 3/8 inches

Step-by-step explanation:

let 'x' = distance in 1 hr, 25 minutes (which is 85 minutes)

(3/8 ÷ 5) = x ÷ 85

cross-multiply:

5x = 255/8

40x = 255

x = 6 3/8

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4 0
3 years ago
Given that 8x – 3y = 36
Vedmedyk [2.9K]

Answer:

x = 45/8

Step-by-step explanation:

8x – 3y = 36

Let y=3

8x – 3*3 = 36

8x - 9 = 36

Add 9 to each side

8x -9+9 = 36+9

8x = 45

Divide each side by 8

8x/8 = 45/8

x = 45/8

4 0
3 years ago
Read 2 more answers
0.30 meters to customary units of length
Vlada [557]
 It would be .98 feet or 11.81 inches
8 0
3 years ago
Find an antiderivative F(x) with F′(x) = f(x) = 6 + 24x^3 + 18x^5 and F(1)=0.
7nadin3 [17]

Answer:

The antiderivative is F(X) = 6x + 6x^4 + 3x^6 - 15.

Step-by-step explanation:

Antiderivative F(x)

This is the integral of F^{\prime}(x)

So

F′(x) = f(x) = 6 + 24x^3 + 18x^5

Then:

F(x) = \int (6 + 24x^3 + 18x^5) dx

F(x) = 6x + \frac{24x^4}{4} + \frac{18x^6}{6} + K

F(x) = 6x + 6x^4 + 3x^6 + K

F(1)=0

F(X) = 0 when x = 1. We use this to find K.

F(x) = 6x + 6x^4 + 3x^6 + K

0 = 6 + 6 + 3 + K

K = -15

Thus

The antiderivative is F(X) = 6x + 6x^4 + 3x^6 - 15.

7 0
3 years ago
Find the difference quotient of f(x)=5x+4
Aleonysh [2.5K]
The differnce quotient is basically taking the derivitive (result will be f'(x)=5, but anyway)

here is the disffernce quotient
lim_{h\rightarrow0}\frac{f(x+h)-f(x)}{h}

so
for your equation
lim_{h\rightarrow0}\frac{(5(x+h)+4)-(5x+4)}{h}
lim_{h\rightarrow0}\frac{5x+5h+4-5x-4}{h}
lim_{h\rightarrow0}\frac{5h}{h}
h's cancel and you are left with 5
the differnce quotient is 5
6 0
3 years ago
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