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MakcuM [25]
3 years ago
6

What mistake did Brianna make? On Line 1, Brianna should have subtracted 3 instead of adding -3. On Line 1, Brianna violated the

addition property of equality. On Line 3, Brianna should have divided by 0.1 instead of subtracting 0.1. On Line 3, Brianna violated the addition property of equality.
Mathematics
2 answers:
yarga [219]3 years ago
7 0

Question:

Brianna solved a two-step equation, but she made a mistake along the way.

0.1x + 3 = 1.7

Line 1 : (-3) + 0.1x + 3 = 1.7 + (-3)

Line 2 : 0.1x = -1.3

Line 3 : (-0.1) + 0.1x = -1.3 + (-0.1)

Line 4: x = -1.4

Answer:

On Line 3, Brianna should have divided by 0.1 instead of subtracting 0.1.

Step-by-step explanation:

Required

Where did she make a mistake?

To do this, we simply analyse her workings one step at a time

Equation: 0.1x + 3 = 1.7

Line 1 : (-3) + 0.1x + 3 = 1.7 + (-3)

This is correct because she subtracted 0.3 from both sides

Line 2 : 0.1x = -1.3

This is also correct because she performed the arithmetic correctly

Line 3 : (-0.1) + 0.1x = -1.3 + (-0.1)

This is incorrect.

Division by 0.1 is expected not subtraction

Ymorist [56]3 years ago
7 0

Answer:

It's C

Step-by-step explanation:

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mixas84 [53]

Answer:

<em>Option c</em>

Step-by-step explanation:

<u>Best Fit Regression Model </u>

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One of the most-used tools to find relations between variables is the regression model and its best fit lines to try to find an expression who relates variable x (years from 1960) and variable y (minimum wage requirement) as of our case.

The provided data was entered into a digital spreadsheet and an automatic function was applied to find the best-fit model.

We found this equation:

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when rounded to three decimal places, we find

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7 0
3 years ago
The graph of F(x) shown below has the same shape as the graph of G(x) = x^2 but it is shifted down 5 units and to the left 4 uni
grandymaker [24]

\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}\\ ~~~~~~\textit{reflection over the x-axis}

\bf \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}\\\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}


with that template in mind, let's see

down by 5 units, D = -5

to the left by 4 units, C = +4


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earnstyle [38]

Answer:

6/8

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4 0
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Makovka662 [10]

Answer:

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Step-by-step explanation:

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9-6=3

7 0
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