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andrew-mc [135]
3 years ago
6

NEED ANSWERED NOW

Mathematics
2 answers:
exis [7]3 years ago
7 0

The function is negative when x < 0 as shown by the graph.

The function does increase. Look at the graph.

Therefore the answer is C.

bekas [8.4K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

I was solving steps and I kept seeing 0 so I dont if I'm completely sure but I hope im right

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Instructions: Type the correct answer in each box. If necessary, use / for the fraction bar.
Alinara [238K]
The slope of diagonal <em>AB</em> is 0 and its equation is y=2.
7 0
2 years ago
The equation of line p is y= -7/8x + 3/2. line q is parallel to line p. what is the slope of line q?
zimovet [89]

Answer:

-7/8

Step-by-step explanation:

If two lines are parallel, they have the same slope. The slope of p is -7/8 (y=mx+b), so the slope of q is also -7/8.

4 0
3 years ago
Need help with this plz
gogolik [260]

Answer:

x =  \frac{ - 24 \pm \sqrt{ - 288} }{4}  \\  =  \frac{ - 24 \pm \sqrt{ ( - 1) {(12)}^{2} (2)} }{4} \\  =   \frac{ - 24 \pm \sqrt{ - 1}  \sqrt{ {12}^{2} } \sqrt{2}  }{4} \\  =   \frac{ - 24 \pm i 12\sqrt{2}  }{4} \\  =-\frac{24}{4}\pm \frac{i12\sqrt{2}}{4}\\=  -  6  \pm \: i3 \sqrt{2}

3 0
2 years ago
The perimeter of a rectangle is 34 units. Its width is 6.5 point, 5 units.
12345 [234]
<h3><u>Question:</u></h3>

The perimeter of a rectangle is 34 units. Its width W is 6.5 units.

Write an equation to represent the perimeter in terms of the length L, and find the value of L

<h3><u>Answer:</u></h3>

The length of rectangle is 10.5 units

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangle = 34 units

Width of rectangle = 6.5 units

Let "L" be the length of rectangle

<em><u>The perimeter of rectangle is given by formula:</u></em>

Perimeter = 2(length + width)

<em><u>Substituting the values we get,</u></em>

34 = 2(L + 6.5)

Thus the equation is found

<em><u>Solve for "L"</u></em>

L + 6.5 = \frac{34}{2}\\\\L + 6.5 = 17\\\\L = 17 - 6.5\\\\L =10.5

Thus length of rectangle is 10.5 units

6 0
3 years ago
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