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baherus [9]
3 years ago
11

Which equation is equivalent to the equation b sin(A) = a sin(B)? StartFraction a Over sine (uppercase B) EndFraction = StartFra

ction b Over sine (uppercase A) EndFraction StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction StartFraction sine (uppercase A) Over sine (uppercase B) EndFraction = StartFraction b Over a EndFraction StartFraction sine (uppercase B) Over a EndFraction = StartFraction sine (uppercase A) Over b EndFraction.
Mathematics
2 answers:
Luda [366]3 years ago
4 0

Answer:

its B

Step-by-step explanation:

i got it right on edge 2022

ella [17]3 years ago
3 0

Answer:

The correct answer is B

Step-by-step explanation:

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When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve
Akimi4 [234]

Answer:

5\frac{3}{10}  cans extra food is needed to feed the second cat.

Step-by-step explanation:

Given:

When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve a total of 11/2 cans each day.

Now, to find the extra food is needed to feed the second cat.

Food needed for one cat = \frac{1}{5}\ of\ can.

Food needed for both one and second cat needed = \frac{11}{2}\ =5\frac{1}{2}\ cans.

Now, extra food needed to feed the second cat:

<u><em>Food needed for both one and second cat needed - food needed for one cat.</em></u>

<u><em /></u>\frac{11}{2} -\frac{1}{5}\\\\=\frac{55-2}{10} \\\\=\frac{53}{10}<u><em /></u>

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Therefore, 5\frac{3}{10}\ cans extra food is needed to feed the second cat.

5 0
3 years ago
A rectangular prism has a length of 10ft, a height of 3ft, and a width of 4ft. What is its volume, in cubic ft?
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Ymorist [56]

Answer:

y-intercept: y=0

axis of symmetry: x=0

vertex: (0,0)

Step-by-step explanation:

To find the y-intercept, set x = 0 and solve for y.

I am assuming f(x) = y

y=4x^2

y=4(0)^2

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The y-intercept of the equation is y = 0.

Now, for the axis of symmetry, you need the equation x=\frac{-b}{2a}

In an equation.. y=ax^2+bx+c

In this case, there is only an a, so plug in the values into the equation.

x=\frac{0}{2(4)}

x=0

The axis of symmetry is x = 0.

To find the vertex, change the format of the equation from standard form to vertex form.

Vertex form: y=a(x-h)^2+k

The vertex is (h,k)

y=4x^2 = 4(x+0)^2+0

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The vertex in this case is (0,0).

Graphing makes things a lot easier. If you can graph it, all you have to do is look at the graph and the answers are all there!

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