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irinina [24]
3 years ago
8

Someone please help thank you! (:

Mathematics
1 answer:
Cloud [144]3 years ago
8 0
D
Just plug in the coordinates to each answer choice with a slope of 3 (ACD) and see which one is true
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Joshua cashed a check for $16.79he asked the teller to give him as many quarters as possible .how many quarters did he get
Verizon [17]

Answer:

67 quarters

Explanation:

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2 years ago
Find variable values for two variables in an equation
never [62]

Simplifying

2x + 3y = 12

Solving

2x + 3y = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3y' to each side of the equation.

2x + 3y + -3y = 12 + -3y

Combine like terms: 3y + -3y = 0

2x + 0 = 12 + -3y

2x = 12 + -3y

Divide each side by '2'.

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x = 6 + -1.5y

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3 years ago
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Answer:

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Step-by-step explanation:

it is the answer you need i have tried my best

3 0
3 years ago
QUESTION 39.1 POINT
Levart [38]

Answer:

The Z-score when x = 76 is of -0.125, which tells you that x = 76 is 0.125 standard deviations to the left of the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X ~ N(77,8).

This means that \mu = 77, \sigma = 8

Z-score when X = 76:

Z = \frac{X - \mu}{\sigma}

Z = \frac{76 - 77}{8}

Z = -0.125

Negative means that its to the left of the mean.

The Z-score when x = 76 is of -0.125, which tells you that x = 76 is 0.125 standard deviations to the left of the mean.

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3 years ago
Find f(2) if f(x)=|x+1| ^2<br> 9<br> 6<br> 5
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9. trust

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