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vredina [299]
3 years ago
8

Suppose you borrow 13,000 for four years at 7% toward the purchase of a car.

Mathematics
1 answer:
dangina [55]3 years ago
5 0
Amount borrowed, P = 13000
Interest, i = 0.07/12 per month
number of periods (months),  n = 4*12 = 48

Monthly payment, 
A=\frac{P(i*(1+i)^n)}{(1+i)^n-1}
=\frac{13000(.07/12*(1+.07/12)^{48}}{(1+.07/12)^{48}-1}
=311.30   (to the nearest cent)
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When f(n) = 34, what is the value of f(n-6)?
Mashutka [201]

Answer:

28

Step-by-step explanation:

f(n)=34, f(n-6)=34-6

=28

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2 years ago
Is each line parallel, perpendicular, or neither parallel nor perpendicular to the line −3x+5y=−15 ?
AysviL [449]
Perpendicular means that it has a slope that is the reciprocal of the original, and parallel means that the slopes are the same.
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In a study of the progeny of rabbits, Fibonacci (ca. 1170-ca. 1240) encountered the sequence now bearing his name. The sequence
expeople1 [14]

The question in part c is not clear, nevertheless, part a and part b would be solved.

Answer:

a. The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

b. The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

Step-by-step explanation:

a. Given

an + 2 = an + an + 1

where a1 = 1 and a2 = 1.

a3 = a1 + a2

= 2

a4 = a2 + a3

= 3

a5 = a3 + a4

= 5

a6 = a5 + a4

= 8

a7 = a6 + a5

= 13

a8 = a7 + a6

= 21

a9 = a8 + a7

= 34

a10 = a9 + a8

= 55

a11 = a10 + a9

= 89

a12 = a11 + a10

= 144

The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

(b)

Given

bn = an+1/an

b1 = a2/a1

= 1/1 = 1.000

b2 = a3/a2

= 2/1 = 1.000

b3 = a4/a3

= 3/2 = 1.500

b4 = a5/a4

= 5/3 = 1.667

b5 = a6/a5

= 8/5 = 1.600

b6 = a7/a6

= 13/8 = 1.625

b7 = a8/a7

= 21/13 = 1.615

b8 = a9/a8

= 34/21 = 1.619

b9 = a10/a9

= 55/34 = 1.618

b10 = a11/a10

= 89/55 = 1.618

The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

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Answer:

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