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zhuklara [117]
3 years ago
9

Which of the following is a trinomial with a constant term ?

Mathematics
1 answer:
Katarina [22]3 years ago
5 0
It’s A because a trinomios has three terms and the last digit 12 doesn’t change unlike 2y which changes with every input of y.
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Please help please I need someone to tell me quick
Debora [2.8K]

Answer:

53.19 each day

Step-by-step explanation:

4 0
3 years ago
The grocery store has a sale on canned tomatoes: 4 cans for $5.00. Find the unit rate (cost per can).​
Ymorist [56]

Answer:

For every can, it would be $1.25.  1 can= $1.25

Step-by-step explanation:

For every 4 cans, it is $5, 4:5

if you divide both sides by 4. it would 1:1.25

So, for every can, it would be $1.25

8 0
3 years ago
Find an equation in slope intercept form of a line having slope 6 and y-intercept 2
xz_007 [3.2K]

Answer:

<h2>y = 6x + 2</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the slope <em>m = 6</em>, and the y-intercept <em>b = 2</em>.

Substitute:

y=6x+2

4 0
3 years ago
What is the measure of angle A in the triangle below? Right triangle A B C is shown. Side B C has a length of 9 and hypotenuse A
klasskru [66]

Answer:

The answer is 30°

Step-by-step explanation:

I finished the test on edgen and passed

8 0
3 years ago
A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 19 randomly selected pens yield
Romashka [77]

Given Information:  

Probability of shipment accepted = p = 5%

Probability of shipment not accepted = q = 95%

Total number of pens = n = 19

Required Information:  

Probability of shipment being accepted with no more than 2 defective pens = P( x ≤ 2) = ?  

Answer:

P( x ≤ 2) = 0.933

Step-by-step explanation:

The given problem can be solved using Bernoulli distribution  which is given by

P(n, x) = nCx pˣqⁿ⁻ˣ  

The probability of no more than 2 defective pens means

P( x ≤ 2) = Probability of 0 defective pen + Probability of 1 defective pen + Probability of 2 defective pens

P( x ≤ 2) = P(0) + P(1) + P(2)

For P(0) we have p = 0.05, q = 0.95, n = 19 and x = 0

P(0) = 19C0(0.05)⁰(0.95)¹⁹

P(0) = (1)(1)(0.377)

P(0) = 0.377

For P(1) we have p = 0.05, q = 0.95, n = 19 and x = 1

P(1) = 19C1(0.05)¹(0.95)¹⁸

P(1) = (19)(0.05)(0.397)

P(1) = 0.377

For P(2) we have p = 0.05, q = 0.95, n = 19 and x = 2

P(2) = 19C2(0.05)²(0.95)¹⁷

P(2) = (171)(0.0025)(0.418)

P(2) = 0.179

Therefore, the required probability is

P( x ≤ 2) = P(0) + P(1) + P(2)

P( x ≤ 2) = 0.377 + 0.377 + 0.179

P( x ≤ 2) = 0.933

P( x ≤ 2) = 93.3%

Therefore, the probability that this shipment is accepted with no more than 2 defective pens is 0.933.

8 0
3 years ago
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