All categories

3 years ago

If m<1 = 38 then m<4 =

Mathematics

1 answer:

Mariana [72]3 years ago

4 0

Answer:

If m<1 = 38 then m<4 = 38

Step-by-step explanation:

Both of the angles equal 38 degrees. This is true because the angles are vertical, vertical angles are angles opposite each other where two lines cross. Vertical angles are also always congruent, therefore the m<4=38.

You might be interested in

I really need help with this geometry on number 7 like help please!!

vredina [299]

Solution: 137 / 2 = 68.5

LMP is 11 degress more so 68.5 + 11 = 79.5

NMP is 11 degrees less so 68.5 - 11 = 57.5

3 0

3 years ago

Dean has $70 in a savings account that earns 5% interest, compounded annually. To the nearest cent, how much will he have in 3 y

SSSSS [86.1K]

Answer:

lmjtntndadwtwpwpwpmpmwpmpmq

8 0

3 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

3 years ago

The table below shows the functions to represent the sale f(t), in thousands, of four companies in t years:

Irina-Kira [14]

Choice C , Company C and Company D. hope I helped.

4 0

3 years ago

Read 2 more answers

During the first year, ABC's stock price starts at $ \$100 $ and increases $ 100\% $. During the second year, its stock price go

Artemon [7]

Answer:

Step-by-step explanation:

During the first year, ABC's stock price starts at $100 and increases by 100%. This means that the amount by which the stock increased would be

100/100 × 100 = $100

The new price of the stock would be 100 + 100 = $200

During the second year, its stock price goes down 25% from its price at the end of the first year. This means that the amount by which the stock reduced is

25/100 × 200 = 0.25 × 200 = $50

Therefore, the price of the stock, in dollars, at the end of the second year is

200 - 50 = $150

6 0

3 years ago

Read 2 more answers