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nekit [7.7K]
2 years ago
14

Using the formula below, calculate the z-score for the listed data points. z-score: zx = x − μ σ z1 = z5 = z6.5 =

Mathematics
2 answers:
wel2 years ago
5 0

Answer:

z1 = -1.95

z5 = 0.05

z6.5 = 0.8

Step-by-step explanation: Good luck! :D

lisabon 2012 [21]2 years ago
4 0

Answer:

z1 = -1.95

z5 = 0.05

z6.5 = 0.8

Step-by-step explanation:

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In triangle ABC, and C is a right angle. Find the value of the trig function find the sec(A) if C=25, B=20, A=15
asambeis [7]

Answer:

sec A = 5/4

Step-by-step explanation:

Sec of an angle is hypotenuse/adjacent side

In your problem, sec A = 25/20 = 5/4

It helps if you can draw a figure of the problem.  Make sure you memorize the definition of each trig function

5 0
3 years ago
What do you find at the intersection of a plane and line?
Viktor [21]

You find a point at the intersection of a plane and line.

6 0
3 years ago
Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl
katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

brainly.com/question/22599425

8 0
2 years ago
Read 2 more answers
PLEASE HURRY :,) WILL GIVE BRAINLEST
Vlad1618 [11]

Answer:

Point R is at (-40,30),  a distance of 60 units from point Q

Step-by-step explanation:

<u>Explanation </u>

<u>we will use below conditions</u>

<u>Type of transformation</u>                                 <u> change to co-ordinate point</u>

  1. vertical translation up 'd' units                (x, y) changes to (x, y +d)
  2. vertical translation down 'd' units            (x, y) changes to (x, y-d)
  3. horizontal translation left 'c' units            (x, y)  changes to (x- c, y)  

   4. horizontal translation right 'c' units         (x, y) changes to (x+ c , y)

now Given data is P( 20,-30) and in the graph Q(-40,-30)

Step1:-

<u>Now we have to find 'R' point</u>

Given data the point "R' is vertically above point Q so the point "Q' is moves vertically up with '60' units

now we will use the condition (1)

Q(-40,-30) is <u>vertical translation up '60' units </u>now changes the co-ordinate point is (-40 , -30+60)

<u>The correct translation and The point R( -40 , 30)</u>

<u>Step2:-</u>

Again in the given data  "R" is at the same distance from point Q as point P is from point Q.

<u>so given P point is (20 , -30)</u>

now we translation 'P' also

<u>vertically translation up at a distance '60' units</u> and changes the new co-ordinate (20 , -30+60) that is (20,30)  [ use above condition  is (1)]

and again<u> horizontal translation left '60</u>' now changes (20 - 60 ,30)[ use condition (3)]

There fore the new co-ordinate is R( -40 , 30)

<u>Final answer:-</u>

Point R is at (−40, 30), a distance of 60 units from point Q

6 0
3 years ago
Which of the following functions results in a graph that shows exponential decay? f(x) = 4(0.8)x f(x) = 0.7(1.2)x f(x) = 12(3)x
Korvikt [17]

The function will show exponential decay if one of the following is true

  • the base is less than 1 and the exponent is positive
  • the base is greater than 1 and the exponent is negative

The function that meets the requirement for exponential decay is ...

f(x)=4\cdot 0.8^{x}\quad\text{matches the first choice}

5 0
3 years ago
Read 2 more answers
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