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Veronika [31]
3 years ago
15

Help please

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

192

Step-by-step explanation:

3(pi) x 4^2 x 12 ÷ 3 = 192

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Answer:

Please don't report me.

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What is the question because you don't specify put a comment and I will edit my answer.

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4 years ago
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1. y = -2 √(25-x ) +8<br><br> 2. y = -3 √(x+ 9) +4<br><br> Please help
tensa zangetsu [6.8K]

<u>X AND Y INTERCEPTS</u>

1st Answer:

x = 9

Step-by-step explanation:

<u>first you want to substitute the y</u>

<h3>0 = -2 √(25 - x + 8)</h3>

<u>move the expression to the left</u>

<h3>2 √(25 - x) = 8</h3>

<u>divide both sides</u>

<h3>√25 - x + 4</h3>

<u>move the constant to the right</u>

<h3>25 - x = 16</h3>

<u>calculate</u>

<h3>-x = -9</h3>

<u>change the signs</u>

<h3>x = 9</h3><h3></h3>

2nd Answer:

x = -65/9  OR x = - 7 2/9, x = - 7.2

Step-by-step explanation:

<u>first you want to substitute the y</u>

<h2>0 = -3 √(x + 9) = 4</h2>

<u>move the expression to the left</u>

<h2>3√(x+9) = 4</h2>

<u>divide both sides</u>

<h2>√(x+9) = 4/3</h2>

<u>move the constant to the right</u>

<h2>x = 16/9 - 9</h2>

<u>calculate</u>

<h2>x = -65/9</h2>

7 0
3 years ago
How many ways are there to choose two queens from a standard 52-card deck?
ivann1987 [24]
There are four queens is a standard deck, so 4.3 = 12 options

to any three cards = 52.51.50 = 132600 ways

Two queens in a random draw = 48. 2. 2. 47.46 = 2.283.072 hands

Two of a kind = 52/4 = 13. Then every kind has 13 cards.

13.12.13.13 = 26.354

8 0
3 years ago
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