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dybincka [34]
3 years ago
13

Do these ratios form a proportion?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
8 0

Answer:

Yes, 5:7 and 5:7

Step-by-step explanation:

Delicious77 [7]3 years ago
5 0
YESSSSSSSSSSSSS. Sssssssssss.
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Look at photo please
amm1812

Answer:

A

Step-by-step explanation:

combining 10² and 10² makes 10⁴.

combining 1.5 and 1 makes 2.5.

so you have 10⁴ x 2.5, which is the same as the part on the other side of the equals symbol, making the equation true. All the other equations are false.

5 0
3 years ago
Rearrange y=1/2x+2 to make x the subject.
yarga [219]

Subtract 2

y-2=1/2 x

Multiply by 2 to cancel out the denominator and to get 1 in front of x

2(y-2)=x

You can stop there or you can multiply out.

2y-4=x


7 0
3 years ago
Read 2 more answers
PLZ HELP <br>5³×25<br>how do you solve​
Dennis_Churaev [7]
Answer: 3125
5x5x5=125
125x25=3125
7 0
3 years ago
Read 2 more answers
The graph of which function passes through (0,4) and has a minimum value at (StartFraction 3 pi Over 2 EndFraction, 3)? f (x) =
solniwko [45]

Answer:

f(x) = sin(x) + 4  Let me know if you don't see why.

Step-by-step explanation:

As much as I hate it I think it might be best to check each one.  

sin(x) has a point at (0,0) so that's not right.

sin(x)+4 has (0,4) as a point and a minimum at (3*pi/2+2*pi*n,3) where n is some integer.  if we have n = 0 then it becomes (3*pi/2, 3) So that looks like our answer.

cos(x) + 3 has a point at (0,4) then minimums at (pi+2*pi*n, 2)  the y coordinate is wrong so this won't work

-3sin(x) has a point at (0,0) so that's wrong

4cos(x) has a point at (0,4) then minimums at (pi+2*pi*n, -4) which again has the wrong y value so this is wrong.

Let me know if you don't understand how I got the results I did, I would be happy to explain.  

7 0
3 years ago
Read 2 more answers
Which equation represents the formula for the general term, gn, of the geometric sequence 3, 1, 1/3, 1/9, . . .?
dedylja [7]

Answer:

Explicit form: g_n=3(\frac{1}{3})^{n-1}

Recursive form: g_n=\frac{1}{3}g_{n-1} with g_1=3.

Step-by-step explanation:

The first term is 3 and we are dividing by 3 each time.

Another way to say we are dividing by 3 each time is to say we are multiplying by factors of 1/3.

If the first term is a and r is the common ratio then the geometric sequence in explicit form is:

a_n=a(r)^{n-1}

g_n=3(\frac{1}{3})^{n-1}

The recursive form for a geometric sequence is a_n=ra_{n-1} with a_1=a where r is the common ratio and a is the first term.

So the recursive form for our sequence is g_n=\frac{1}{3}g_{n-1} with g_1=3.

6 0
3 years ago
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