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2 years ago

Help me plz NO LINKS

Mathematics

1 answer:

kiruha [24]2 years ago

8 0

Y=2
Since the table (y) increase by 2 each time the answer would be y=2

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Identifiy the initial amount a and the decay factor b in the exponential function y=5×0.5^×

xenn [34]

Answer:

$a=5\\ \\b=0.5$

Step-by-step explanation:

Given the exponential decay function $y=5\cdot (0.5)^x$

When $x=0,$ then

$y=5\cdot (0.5)^0=5\cdot 1=5,$

so the initial amount is $a=5$

The exponential decay function $y=a\cdot b^x$ has the decay factor $b.$

In your case, the eexponential decay factor is $b=0.5$

6 0

3 years ago

Please answer ASAP! BRAINLIEST IF CORRECT!

mezya [45]

Answer:

63.66197728% or just 64% lol

Step-by-step explanation:

8 0

3 years ago

Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?

natima [27]

Answer:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

Step-by-step explanation:

The question is poorly formatted. The original question is:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

We have:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

Open bracket

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 8 as 2^3

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 2^3 as 8

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}$

Expand each exponent

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}$

Split

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}$

Factorize

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

4 0

3 years ago

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Given h(x) = x^2-4/2, find h(-8)

vlada-n [284]

Answer:

Step-by-step explanation:

(-8)^2-2

64-2 = 62

7 0

3 years ago

Riangle ABC is isosceles. Triangle A B C is shown. The lengths of sides A C and A B are congruent. What is true about the measur

sesenic [268]

Answer: It is equal to the measure of angle C.

Step-by-step explanation:

If we know that Triangle ABC isosceles, then that means two sides and two angles are congruent to each other. Angle A must the topmost angle, and Angle B and C are probably the base angles. So, saying that, the base angles and sides are congruent to each other. Hence, Angle B must be equal to Angle C.

6 0

3 years ago

Read 2 more answers