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timofeeve [1]
3 years ago
8

Rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin. What are the coordinates of the

image of point B prime? On a coordinate plane, rectangle A B C D has points (negative 8, 6), (negative 4, 6), (negative 4, 4), (negative 8, 4). (–2, 3) (3, –2) (–8, 12) (12, –8)
Mathematics
2 answers:
Svetach [21]3 years ago
5 0

Answer:

The new coordinate of image of point B (-4, 6) will be B'(-2, 3) when a rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin.

Step-by-step explanation:

Considering the vertices of the rectangle ABCD

A(-8, 6)

B(-4, 6)

C(-4, 4)

D(-8, 4)

When a rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin, then the coordinate of image of point B can be calculated by multiplying the x and y coordinates of point B with 1/2.

i.e.

B(-4, 6) → B'(-4/2, 6/2) = B'(-2, 3)

Therefore, the new coordinate of image of point B (-4, 6) will be B'(-2, 3) when a rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin.

Strike441 [17]3 years ago
5 0

Answer:

Its (-2, 3) or Answer A

Step-by-step explanation:

Its the correct answer for edg

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Match it with x and y method

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Svetlanka [38]

La pregunta está incompleta ya que no se da el costo de la colocación de baldosas por m².

Suponga que el costo de los mosaicos por m² = c

Respuesta:

39.06c

Explicación paso a paso:

El costo del embaldosado será:

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Dado que :

La dimensión de la habitación a embaldosar es:

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El área total de la habitación a embaldosar es = Largo * ancho

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4 0
4 years ago
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

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and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

(x-h)^{2}+(y-k)^{2}=r^{2}

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(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100

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arsen [322]
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8 0
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