Answer:
The system has infinite solutions described in the set 
Step-by-step explanation:
The augmented matrix of the system is ![\left[\begin{array}{cccc}-1&-1&-1&4\\2&1&0&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%26-1%26-1%264%5C%5C2%261%260%262%5Cend%7Barray%7D%5Cright%5D)
.
We apply row operations:
1. We add the first row to the second row twice and obtain the matrix ![\left[\begin{array}{cccc}-1&-1&-1&4\\0&-1&-2&10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%26-1%26-1%264%5C%5C0%26-1%26-2%2610%5Cend%7Barray%7D%5Cright%5D)
2. multiply by -1 the rows of the previous matrix and obtain the matrix ![\left[\begin{array}{cccc}1&1&1&-4\\0&1&2&-10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%26-4%5C%5C0%261%262%26-10%5Cend%7Barray%7D%5Cright%5D)
that is the reduced echelon form of the matrix associated to the system.
Now we aply backward substitution:
1. Observe that the reduced echelon form has a free variable, then the system has infinite solutions.
2.
3.
.
Then the set of solutions is
Answer:
The expression can be given as : 
Step-by-step explanation:
Though any options are not given, but the question is complete so we can solve this by assuming the initial price of the property to be = x
Given, that the price is increased by 275%, this means x+x(275%)
275% can be written as : 
So, the expression can be given as :
The gcf of 100 and 20 would be 5. hopefully that's right, and that this helped.
P(x) = x^4 - 9x^2 - 4x + 12
P(1) = 1^4 - 9(1)^2 - 4(1) + 12 = 1 - 9 - 4 + 12 = 0
x = 1 is a root.
By dividing the polynomial by x - 1, gives other roots as 3 and -2
Answer:
1, 17, 33, 49
Step-by-step explanation:
given the first term is 1 then the next 3 terms are
1 + d, 1 + 2d, 1 + 3d ( d is the common difference )
the sum of the first 4 terms is 100 , then
1 + 1 + d + 1 + 2d + 1 + 3d = 100 , that is
4 + 6d = 100 ( subtract 4 from both sides )
6d = 96 ( divide both sides by 6 )
d = 16
1 + d = 1 + 16 = 17
1 + 2d = 1 + 2(16) = 1 + 32 = 33
1 + 3d = 1 + 3(16) = 1 + 48 = 49
the first 4 terms are
1, 17, 33, 49
