Answer:
Step-by-step explanation:
Solution by substitution method
3x-4y=8
and 18x-5y=10
Suppose,
3x-4y=8→(1)
and 18x-5y=10→(2)
Taking equation (1), we have
3x-4y=8
⇒3x=4y+8
⇒x=(
4y+8)/
3 →(3)
Putting x=
(4y+8
)/3 in equation (2), we get
18x-5y=10
18(
(4y+8)
/3) -5y=10
⇒24y+48-5y=10
⇒19y+48=10
⇒19y=10-48
⇒19y= -38
⇒y=-
38
/19
⇒y= -2→(4)
Now, Putting y=-2 in equation (3), we get
x=4y+8
x=
(4(-2)+8)
/3
⇒x=
(-8+8)/
3
⇒x=
0/
3
⇒x=0
∴x=0 and y= -2
I don't know what you mean by unknown factor but a quotient is the answer of a division problem
Answer:
the Peter age be 27
Step-by-step explanation:
Let assume peter be
And, then mary is 2p ÷ 3
So
The equation would be
2p ÷ 3 - 2 = 1 ÷ 2 (p + 5)
4p - 12 = 3p + 15
p = 27
So Peter age be 27
And, the mary age is
= 2 (27) ÷ 3
= 18
Hence, the Peter age be 27
Answer:
7/10
Step-by-step explanation:
Answer:
59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.
Step-by-step explanation:
Step 1
Express the angle of inclination as follows;
Tan∅=H/R
where;
∅=angle of inclination
H=vertical rise
R=distance of run
Step 2
Determine the angle inclination when;
H=3 feet
R=2 feet
replacing;
Tan∅=(3/2)=1.5
∅=Tan^(-1)(1.5)
∅=56.31°
Determine the angle inclination when;
H=5 feet
R=3 feet
replacing;
Tan∅=(5/3)=1.67
∅=Tan^(-1)(1.67)
∅=59.03°
59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.
