Answer:
In 3y-24, 3 is the greatest common factor.
3y-24
=3(y-8)
Equ 1: X-Y=5
equ 2: x∗y=36
from Equ 1
X=5+Y------equ 3
substitute x=5+y in equ 2
(5+y)∗y=36
5y+y^2=36
y^2+5y-36=0
factorize by substitution
(y^2+9y)-(4y-36)=0
y(y+9)-4(y+9)=0
(y-4)(y+9)=0
y=4 or y=-9....
substitute y=4 or -9 in equ 1
x-4=5
x=5+4
x=9 OR
x-(-9)=5
x+9=5
x=5-9
x=-4
since -4∗-9=36
therefore y=-9 and x=-4
Answer:
it
Step-by-step explanation:
i + t = it
Given:
There are two consecutive odd integers such that the square of the first added to 3 times the second, is 24.
To find:
Part a: Define the variables.
Part b: Set up an equations that can be solved to find the integers.
Part c: Find the integers.
Solution:
Part a:
Let x be the first odd integers. Then next consecutive odd integer is
, because the difference between two consecutive odd integers is 2.
Part b:
Square of first odd integers = 
Three times of second odd integers = 
It is given that the sum of square of first odd integers and three times of second odd integers is 24. So, the required equation is:

Part c:
The equation is:

It can be written as:



Splitting the middle term, we get




-6 is not an odd integer, so
and the first odd integer is 3.
Second odd integer = 
= 
= 
Therefore, the two consecutive odd integers are 3 and 5.
Bob has a garden
the area is 75 square feet
the legnth is 3 times the width
solve
75=lw
l=3w
subsitute
75=3w times w=3w^2
75=3w^2
sdivide by 3
25=w^2
square root
5=width
subsitute
3w=l
3 times 5=l
l=15
width=5
legnth=15