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2 years ago

What is the range and domain of the set? :R: {(−11, 16), (17, 23), (2, -13), (7, 4), (-7, −21)}

Mathematics

1 answer:

Ne4ueva [31]2 years ago

3 0

Step-by-step explanation:

the range is the biggest number subtracted by the smallest 23-(-11)= 34

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The polygons are similar. The area of one polygon is given. Find the area of the other polygon.

kap26 [50]

Answer:

90 cm²

Step-by-step explanation:

Given that both triangles are similar, it follows that the ratio of their area equals the square of their corresponding sides.

Let the area of the other triangle be x. Therefore:

$\frac{10}{x} = \frac{4^2}{12^2}$

$\frac{10}{x} = \frac{16}{144}$

Cross multiply

$10*144 = 16*x$

$1440 = 16x$

Divide both sides by 16

90 = x

Area of the other polygon = 90 cm²

4 0

2 years ago

Need help on this math problem of parallelograms.

tamaranim1 [39]

Answer:

z=124 because it opposite

Step-by-step explanation:

6 0

2 years ago

Five less than a number Y is under 20

vodomira [7]

Answer:

Y - 5 < 20

Step-by-step explanation:

5 less than Y translates to:

Y - 5

Under 20 translates to:

< 20

Therefore your answer is

Y - 5 < 20

7 0

2 years ago

Read 2 more answers

Points b,d, and f are midpoints of the sides of triangle ACE. EC=30 and DF= 17 find AC

Margaret [11]

Answer:

Your answer should be AC=2DF=34

Step-by-step explanation:

5 0

2 years ago

Please Help. 25 points. <br>

vodomira [7]

Answer:

$\boxed{x = 7, y = 9, z = 68}$

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

$\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}$

$\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}$

$\boxed{\mathbf{ x = 7, y = 9, z = 68}}$

4 0

2 years ago