The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are 
<h3>How to determine the possible zeros?</h3>
The function is given as:
f(x) = 3x^6 + 4x^3 -2x^2 + 4
The leading coefficient of the function is:
p = 3
The constant term is
q = 4
Take the factors of the above terms
p = 1 and 3
q = 1, 2 and 4
The possible zeros are then calculated as:
So, we have:
Expand
Solve
Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are
Read more about rational root theorem at:
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Step-by-step explanation:
I have no idea if I'm doing it right but my guess would be to take the values that we get from f(x) and g(x) when x = 1. Therefore we get that f(x) is equal to 4 and g(x) is equal to -1. We than just do f/g which is 4/-1 which gives us the final answer of -4 which is option B.
Answer: Option B, -4
7.5 would be my best guess
Answer:
X=5
Step-by-step explanation:
-3x+8=-7
-3x=-15
X=5
