We can work out the first three terms of this quadratic equation with substitution.
The first term of this sequence is where n=1, we can substitute 1 in for n
y=1^2+2(1)-4
y=1+2-4
y=-1
We can do this for the next two terms as well
y=2^2+2(2)-4
y=4+4-4
y=4
For the last term:
y=3^2+2(3)-4
y=9+6-4
y=11
Answer: 7-8
Step-by-step explanation:
7-8 A squared + B squared =c Square
9x9 8x8 10x10 12x12
81 64 100 144
145 244
Answer:
x is 29
Step-by-step explanation:
In a rhombus diagonals bisect perpendicularly.
let the centre point of the rhombus be O.
By seeing the diagram we can say that Angle DBC is congruent to angle ADB.
We can say they are congruent because they are symmetric about the diagonals and also by the principle of parallel lines.
Also ADB is a right angled triangle so ,


Hence the value of x is 29.
If this is for a parabola, then the x-coordinate is -1, since it is directly in the middle of -5 and 3, with 4 spaces on each side (symmetry). The equation is just x = -1 since it just shows the equation of the vertical line which splits the parabola into two equal parts
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