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2 years ago

3) substitute the y=-2x+5 into the equation and solve for x.

Mathematics

1 answer:

zloy xaker [14]2 years ago

5 0

Answer:

x = 3

Step-by-step explanation:

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Solve for x <br> 5(x-10)=30-15x

timofeeve [1]

Answer:

solution :

x = 4

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

5*(x-10)-(30-15*x)=0

Step by step solution :

Step 1 :

Equation at the end of step 1 :

5 • (x - 10) - (30 - 15x) = 0

Step 2 :

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

20x - 80 = 20 • (x - 4)

Equation at the end of step 3 :

20 • (x - 4) = 0

Step 4 :

Equations which are never true :

4.1 Solve : 20 = 0

Step-by-step explanation:

4 0

2 years ago

Solve 6x^2 - 42 = 0 for the exact values of x

GREYUIT [131]

Answer:

The values of x are

$x=-\sqrt{7} , x=\sqrt{7}$

Step-by-step explanation:

we have

$6x^{2}-42=0$

Solve for x

Adds 42 both sides

$6x^{2}-42+42=0+42$

$6x^{2}=42$

Divide by 6 both sides

$6x^{2}/6=42/6$

simplify

$x^2=7$

square root both sides

$x=\pm\sqrt{7}$

therefore

The values of x are

$x=-\sqrt{7} , x=\sqrt{7}$

6 0

2 years ago

Solve the equation for the unknown variable.

olga nikolaevna [1]

Answer:

b x 3 = 8

=> b = 8/3

Hope this helps!

4 0

3 years ago

Please help me!

slava [35]

1/6·30=5
so your answer is b)5

8 0

2 years ago

Read 2 more answers

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers