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Setler79 [48]
3 years ago
9

Y = 1/6x + 8 Identify the y intercept?

Mathematics
2 answers:
Rashid [163]3 years ago
8 0
The y intercept it's eight
jeka943 years ago
7 0

Answer:

(0,8)

Step-by-step explanation:

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Archy [21]

The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

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Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

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