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Mice21 [21]
3 years ago
15

How would you "remove the discontinuity" of f? In other words, how would you define f(5) in order to make f continuous at 5? f(x

) = [(x^2 -2x -15)/x-5]
Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Given f(x) = [(x^2 -2x -15)/x-5], notice it is a rational function

But the numerator x^2 -2x -15 could be factored, which yields

(x – 5)(x + 3)

Therefore f(x) = (x – 5)(x + 3)/ (x-5)

Cancelling x-5, f(x)  = x + 3

In this way, the f(x) is continuous at any point, and is basically a line.

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The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) us
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For this case we must find the point that Harold used to arrive at the following equation:

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In addition, it is observed that x_ {1} = 7and y_ {1} = 0.

Then, the correct option is: Harold used the point (7,0)

ANswer:

When Harold wrote his equation, the point was used (7,0).

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3 years ago
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8 0
4 years ago
12. Sydney Star bought a new sweatshirt for $42.00. Sales tax was 8%.
levacccp [35]

Answer:

$45.36

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6 0
3 years ago
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8 0
3 years ago
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Which function has a range of y &lt; 3?<br> y - 3(2)<br> y = 2(3)<br> O y=-(2)x+ 3<br> Oy- (2) * - 3
defon

Given:

The range of a function is y.

To find:

The function for the given range from the given options.

Solution:

In option A, the given function is:

y=3(2)^x

Here, (2)^x is always greater than 0. So, 3(2)^x is also greater than 0, i.e., y>0.

In option B, the given function is:

y=2(3)^x

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In option C, the given function is:

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-(2)^x+3

y

The range of this function is y. So, option C is correct.

In option D, the given function is:

y=(2)^x-3

Here,

(2)^x>0

(2)^x-3

y

The range of this function is y

Therefore, the correct option is only C.

6 0
3 years ago
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