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sineoko [7]
3 years ago
11

Who invented pascaline and when?​

Computers and Technology
2 answers:
777dan777 [17]3 years ago
7 0

the pascaline was designed and built by the french mathematician - philosopher blasé pascal between 1642 and 1644. It could only do addition and subtraction, with numbers being entered by manipulating it's dials.

The pascaline soon become well known in

France and abroad . The first public description was in 1952 , in the newspaper muse historique. the machine was demonstrated to the public in Paris.

hope this ans help you

thankyou

Mrk me brainilist

Mrrafil [7]3 years ago
3 0

Pascaline, also known as Pascal's calculator or arithmetic machine, was invented by \sf\purple{Blaise\: Pascal} between \sf\red{1642\: and\: 1644}.

\bold{ \green{ \star{ \orange{Mystique35}}}}⋆

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A ___ is a node (or a device) that connects two different networks together and allows them to communicate.
stellarik [79]

Answer:

The answer is Hub

Explanation:

A hub, also called a network hub, is a common connection point for devices in a network. Hubs are devices commonly used to connect segments of a LAN. The hub contains multiple ports. When a packet arrives at one port, it is copied to the other ports so that all segments of the LAN can see all packets.

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3 years ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
An educational institution has a number of buildings in the campus. Each building has its own independent network system, and al
Aloiza [94]
Answer: star topology.

Explanation:

The layout of the way how the computers in a netword are interconnected is called network tipology.

Some types of network topologies are:

1) Point-to-point tipology: all the computers are connected to each other directly (computer-to-computer, in pairs, this is a direct link between each two computers).

2) Bus topology: all the nodes (computers or server) are connectect to a maing cable.

3) Star topology: all the computers are connected to a central computer or server which is called central hub. This is the layout described in the question.

4) Ring topology: the computers are connectec in a circular path; each computer is connected to the next computer.

5) Mesh: every computer is connected to every other computer.




8 0
3 years ago
Read 2 more answers
What is the full form of EPROM (CLASS-6)
vodomira [7]

Answer:

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you use the read csv() function to import the data from the .csv file. assume that the name of the data frame is bars df and the
kumpel [21]

Since you use the read_csv() function to import the data from the .csv file, the code chunk that lets you create the data frame is option C:  flavors_df <- read_csv("flavors_of_cacao.csv")

<h3>What is the aim of chunking?</h3>

Chunking aids in this process by dividing lengthy informational passages into smaller, easier-to-remember bits of information, especially when the memory is being challenged by conflicting inputs.

An R code chunk is a portion of executable code. Calculations will be repeated if the document is reproduced. The benefit of code chunk technology is the decreased possibility of mismatch.

The data frame can be created using the code chunk flavors df - read csv("flavors of cacao.csv"). In this section of code:

The data frame with the name flavors df will hold the information.

  • The assignment operator - is used to give the data frame values.
  • The function read csv() will import the data into the data frame.
  • It read "flavors of cacao.csv" in the file name.
  • the argument that the csv() function accepts.

Learn more about Coding from

brainly.com/question/25525005
#SPJ1

See full question  below

You use the read_csv() function to import the data from the .csv file. Assume that the name of the data frame is flavors_df and the .csv file is in the working directory. What code chunk lets you create the data frame?

Single Choice Question. Please Choose The Correct Option &#x2714;

A

read_csv(flavors_df <- "flavors_of_cacao.csv")

B

read_csv("flavors_of_cacao.csv") <- flavors_df

C

flavors_df <- read_csv("flavors_of_cacao.csv")

D

flavors_df + read_csv("flavors_of_cacao.csv")

5 0
1 year ago
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